40q^2-250=0

Solution for 40q^2-250=0 equation:

40q^2-250=0

a = 40; b = 0; c = -250;
Δ = b2-4ac
Δ = 02-4·40·(-250)
Δ = 40000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{40000}=200$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-200}{2*40}=\frac{-200}{80}
=-2+1/2
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+200}{2*40}=\frac{200}{80}
=2+1/2
$